SOLUTION: I need help in solving the problem y=hg(x)=3.08sqrtx+18.97 where the x is 12

Algebra ->  Square-cubic-other-roots -> SOLUTION: I need help in solving the problem y=hg(x)=3.08sqrtx+18.97 where the x is 12      Log On


   

Question 894776: I need help in solving the problem y=hg(x)=3.08sqrtx+18.97
where the x is 12
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
other than the uncertain notation of hg%28x%29, you have an equation y=3.08%2Asqrt%28x%29%2B18.97, and all you need do is substitute x=12 and evaluate y.