SOLUTION: Simplify (be sure to rationalize all denominators)
10. 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
Here is how I wrote the steps.
1. 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
2. 3
Algebra ->
Square-cubic-other-roots
-> SOLUTION: Simplify (be sure to rationalize all denominators)
10. 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
Here is how I wrote the steps.
1. 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
2. 3
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Question 83596: Simplify (be sure to rationalize all denominators)
10. 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
Here is how I wrote the steps.
1. 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
2. 3b[3a^2SQRT(3ab)] + 2a[a^2b^2SQRT(3ab)]
3. [9a^2+2a^3b^2][SQRT(3ab)]
I am told that there is a small error in the second step. I was also told to notice in the second term,I have SQRT(3a^3b^3).If I remove the perfect square roots,I'll remove only ab, not a^2b^2. I thought that I had the correct answer and am wonder what the correct step and answer are. Thank you for any help you have!
You can put this solution on YOUR website! Simplify: Take the square root of the squares. Simplify. Add the terms.
N.B. In your second step, you failed to take the square root of the and the in the second term when you brought them outside of the radical.