SOLUTION: (4sqrt3)(5sqrt9)<<<< both square roots have an index to the 3rd power.
4*5 * sqrt3 * sqrt9<<< both square roots have an index to the 3rd power.
20sqrt27<< with an index to th
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-> SOLUTION: (4sqrt3)(5sqrt9)<<<< both square roots have an index to the 3rd power.
4*5 * sqrt3 * sqrt9<<< both square roots have an index to the 3rd power.
20sqrt27<< with an index to th
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Question 801151: (4sqrt3)(5sqrt9)<<<< both square roots have an index to the 3rd power.
4*5 * sqrt3 * sqrt9<<< both square roots have an index to the 3rd power.
20sqrt27<< with an index to the 3rd power.
20sqrt3*sqrt9<<<< both with an index to the 3rd power.
20(3)sqrt3 with an index of 3.
60sqrt3 with an index of 3 as my final answer.
Is my final answer correct? what are the errors I have made if any? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (4sqrt3)(5sqrt9)<<<< both square roots have an index to the 3rd power.
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4*cbrt(3)*5*cbrt(9)
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= 20*cbrt(3*9)
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= 20*cbrt(27)
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= 20*3
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= 60
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Cheers,
Stan H.
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