roots of of this equation ; ( x^2+(mx+c)^2=a^2) will be equal if (c^2=a^2(1+m^2))
Expanding the given equation
Rewriting it in standard quadratic form
This is of the form A*x^2 + B*x + C = 0 (I am writing A, B, C in uppercase so
that you don't confuse them with the a,b,c given in the problem)
The roots of the quadratic are equal if the "discriminant" is 0
Discriminant =
-----> (1)
Here A = (1 + m^2) ---> coefficient of x^2 term
B = 2*m*c -----> coefficient of x term
C = c^2 - a^2 -----> constant term
Discriminant(substituting for A,B,C in eqn (1))
=
-> proved!
Hope you got it :)