SOLUTION: how in the world do you do this? thanks! SQRT(4a + 1) = 1 CUBERT(3x - 8) = 1 SQRT(x + 4) = SQRT(x) - 2

Algebra ->  Square-cubic-other-roots -> SOLUTION: how in the world do you do this? thanks! SQRT(4a + 1) = 1 CUBERT(3x - 8) = 1 SQRT(x + 4) = SQRT(x) - 2      Log On


   

Question 768767: how in the world do you do this? thanks!

SQRT(4a + 1) = 1




CUBERT(3x - 8) = 1




SQRT(x + 4) = SQRT(x) - 2
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Limiting just to the CUBERT item:

root%283%2C%283x-8%29%29=1
%28root%283%2C%283x-8%29%29%29%5E3=1%5E3
3x-8=1
3x=1%2B8
3x=9
x=9%2F3=3
x=3