SOLUTION: I was wondering for equation,sqrt(3y+7)= y+1, y =-2&3 -2 because you would get sqrt(3(-2)+7)=-2+1 ==>sqrt (1)=-1, and this works because sqrt 1= -1^2 So would -2 be one of the so

Algebra ->  Square-cubic-other-roots -> SOLUTION: I was wondering for equation,sqrt(3y+7)= y+1, y =-2&3 -2 because you would get sqrt(3(-2)+7)=-2+1 ==>sqrt (1)=-1, and this works because sqrt 1= -1^2 So would -2 be one of the so      Log On


   

Question 762284: I was wondering for equation,sqrt(3y+7)= y+1, y =-2&3
-2 because you would get sqrt(3(-2)+7)=-2+1 ==>sqrt (1)=-1, and this works because sqrt 1= -1^2
So would -2 be one of the solutions?
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

sqrt%283y%2B7%29=+y%2B1....square both sides
%28sqrt%283y%2B7%29%29%5E2=+%28y%2B1%29%5E2
3y%2B7=+y%5E2%2B2y%2B1
0=+y%5E2-3y%2B2y%2B1-7
y%5E2%2B2y-3y-6=0.....group to factor
%28y%5E2%2B2y%29-%283y-6%29+=+0
y%28y%2B2%29-3%28y-2%29+=+0
%28y-3%29%28y%2B2%29+=+0
solutions:
if %28y-3%29+=+0 => y=3
if %28y%2B2%29+=+0 => y=-2