SOLUTION: The maximum number of volts, E, that can be placed across a resistor is given E= sq. rt. PR, where P is the number of watts of power that the resistor can absorb and R is the resis

Algebra ->  Square-cubic-other-roots -> SOLUTION: The maximum number of volts, E, that can be placed across a resistor is given E= sq. rt. PR, where P is the number of watts of power that the resistor can absorb and R is the resis      Log On


   

Question 761004: The maximum number of volts, E, that can be placed across a resistor is given E= sq. rt. PR, where P is the number of watts of power that the resistor can absorb and R is the resistance of the resistor in ohms. Find E if P = 1/2 watts and R = 5000 ohms.
Please show steps. I am very thankful for any help with this. :)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The maximum number of volts, E, that can be placed across a resistor is given E= sq. rt. PR, where P is the number of watts of power that the resistor can absorb and R is the resistance of the resistor in ohms. Find E if P = 1/2 watts and R = 5000 ohms.
----------------
E+=+sqrt%28P%2AR%29+=+sqrt%280.5%2A5000%29
E = 50 volts
===========
That's the step, just doing it.