SOLUTION: How do I solve (2x-5)^2-180=0 Using the square root property?

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Question 715321: How do I solve (2x-5)^2-180=0 Using the square root property?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do I solve (2x-5)^2-180=0 Using the square root property?
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(2x-5)^2 = 180
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2x-5 = sqrt(180) or 2x-5 = -sqrt(180)
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2x-5 = sqrt(36*5) or 2x-5 = -sqrt(36*5)
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2x-5 = 6sqrt(5) or 2x - 5 = -6sqrt(5)
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2x = 5+6sqrt(5) or 2x = 5-6sqrt(5)
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x = (5 + 6sqrt(5))/2 or x = (5-6sqrt(5))/2
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Cheers,
Stan H.
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