SOLUTION: √2 over 2, plus √2 over 3

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Question 712568: √2 over 2, plus √2 over 3

Found 2 solutions by algebrahouse.com, josh_jordan:
Answer by algebrahouse.com(1659) About Me  (Show Source):
You can put this solution on YOUR website!
(√2)/2 + (√2)/3
(3√2)/6 + (2√2)/6 {got common denominator of 6}

5√2
---- {combined numerators over common denominator}
6

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Answer by josh_jordan(263) About Me  (Show Source):
You can put this solution on YOUR website!
To add these two fractions, you must first find the LCD of the fractions:

sqrt%282%29%2F2+%2B+sqrt%282%29%2F3

The LCD (least common denominator) is 6, because 6 is the first number that has 2 and 3 as factors.

So, the next step would be to multiply the numerator and denominator of each fraction by the number that makes the denominator of each fraction equal to 6. In this case, we would multiply the first fraction by 3, because, in order to obtain 6 in the denominator of the first fraction, we have to multiply the numerator and denominator by 3:

%28sqrt%282%29%2A3%29%2F%282%2A3%29, which gives us 3%2Asqrt%282%29%2F6

Next, we would multiply the second fraction by 2, because, in order to obtain 6 in the denominator of the second fraction, we have to multiply the numerator and denominator by 2:

%28sqrt%282%29%2A2%29%2F%283%2A2%29, which gives us 2%2Asqrt%282%29%2F6

Now we can add our fractions together, since our numerators are now the same:

%283%2Asqrt%282%29%2F6%29%2B%282%2Asqrt%282%29%2F6%29 = 5%2Asqrt%282%29%2F6