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Question 70342: m^4+4m^2-12=0
Thank you
Answer by ganit(6)   (Show Source):
You can put this solution on YOUR website! m^4 + 4 m^2 -12 =0
Now find the roots of 12
(6,2) (4,3) In this case since product of two roots is negative one of the roots is negative. The difference between the two is 4.
So the possible set of the roots is (6 , -2).
m^4 + 6 m^2 -2m^2 -12 =0
m^2(m^2+ 6) -2(m^2 + 6) = 0
(m^2-2)* (m^2+6) =0 hence (m^2 -2) =0 or (m^ + 6) =0
m^2 = 2 or m^2 = -6
m= + or - sqrt(2) or m^2 = i^2 * 6
m= + or - i * sqrt(6)
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