SOLUTION: how can u solve this 1.) 2 (sqrt of x+4) = 5 2.) 3t (sqrt of x-1) = 5

Algebra ->  Square-cubic-other-roots -> SOLUTION: how can u solve this 1.) 2 (sqrt of x+4) = 5 2.) 3t (sqrt of x-1) = 5      Log On


   

Question 683984: how can u solve this
1.) 2 (sqrt of x+4) = 5
2.) 3t (sqrt of x-1) = 5
Found 2 solutions by mananth, ReadingBoosters:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
2%28sqrt%28x%2B4%29%29=5
/2
sqrt%28x%2B4%29=+5%2F2
square both sides
x+4 = 25/4
multiply by 4
4x+16=25
4x=25-16
4x=9
x=9/4

Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
1.
2sqrt%28x%2B4%29=5 ==> divide both sides by 2
sqrt%28x%2B4%29+=+5%2F2 ==> square both sides to "undo" the square root
sqrt%28x%2B4%29%5E2+=+%285%2F2%29%5E2
x+4 = 25%2F4==> subtract 4 from both sides
x = 25%2F4+-+4+=+25%2F4+-+4%284%2F4%29+=+25%2F4+-+16%2F4+=+highlight_green%289%2F4%29
...
2. if you are solving for x
3t%28sqrt%28x-1%29%29+=+5 ==> divide both sides by 3t
sqrt%28x-1%29+=+5%2F3t ==> square both sides
sqrt%28x-1%29%5E2+=+%285%2F%283t%29%29%5E2
x - 1 = 25%2F%289t%5E2%29
x =
.....................
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