SOLUTION: (2x^-1y^3z^-2)/(4^-1x^5y^-3z^0)

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Question 643168: (2x^-1y^3z^-2)/(4^-1x^5y^-3z^0)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
(2x^-1y^3z^-2)/(4^-1x^5y^-3z^0)
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= (2y^3/(xz^2))/(x^5*1/(4y^3))
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Invert the denominator and multiply:
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= (2y^3/(xz^2))/(4y^3/x^5*1))
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= (8y^6/(x^6z^2))
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Cheers,
Stan H.
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