SOLUTION: Can you help me sove these equations: 1) square root of 8^4 2) square root of 3y^4x^9 3) square root of 18/75 4) square root of 2x-4=16

Algebra ->  Square-cubic-other-roots -> SOLUTION: Can you help me sove these equations: 1) square root of 8^4 2) square root of 3y^4x^9 3) square root of 18/75 4) square root of 2x-4=16      Log On


   

Question 638287: Can you help me sove these equations:
1) square root of 8^4
2) square root of 3y^4x^9
3) square root of 18/75
4) square root of 2x-4=16
Found 2 solutions by MathLover1, stanbon:
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%288%5E4%29=sqrt%28%288%5E2%29%5E2%29=8%5E2=64
3y%5E4x%5E9=y%5E2%2Ax%5E%289%2F2%29sqrt%283%29

I am not quite sure what you are given here 4) square root of 2x-4=16
if you are given
sqrt%282x-4%29=16, then
%28sqrt%282x-4%29%29%5E2=16%5E2
2x-4=256
2x=256%2B4
2x=260
x=260%2F2
x=130

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
sove these equations:
1) square root of 8^4 = 8^2 = 64
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2) square root of 3y^4x^9 = sqrt(y^4*x^8*3x) = y^2*x^4*sqrt(3x)
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3) square root of 18/75 = sqrt(9*2)/sqrt(25*3) = (3sqrt(2))/(5sqrt(3))
= (3sqrt(6)/(5sqrt(9) = 3sqrt(6)/15 = (1/5)sqrt(6)
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4) square root of 2x-4=16
Question: Is it sqrt(2x)-4 or is it sqrt(2x-4)?
Cheers,
Stan H.