SOLUTION: what is 3 inside the radical of 243x^8 ?
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Question 630621
:
what is 3 inside the radical of 243x^8 ?
Answer by
dfrazzetto(283)
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pull out the perfect cubes:
243 = 9 x 27, 27 is 3 cubed
x^8 = x^2(x^6), cube root of x^6 is x^2
answer is 3x^2(cube root of (9x^2))