SOLUTION: I thought I had the right answer but it came back as wrong. Can someone please let me know how to work this?
1/square root 3 + square root 3
*I got 4/square root 3
Thanks
Algebra ->
Square-cubic-other-roots
-> SOLUTION: I thought I had the right answer but it came back as wrong. Can someone please let me know how to work this?
1/square root 3 + square root 3
*I got 4/square root 3
Thanks
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Question 59528: I thought I had the right answer but it came back as wrong. Can someone please let me know how to work this?
1/square root 3 + square root 3
*I got 4/square root 3
Thanks! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! (1/square root 3 )+ square root 3
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(1/sqrt3) + sqrt3
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Create sqrt3 as the denominator of both fractions:
(1/sqrt3) + (sqrt3)^2/sqrt3
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Now add the numberators to get:
(1+(sqrt3)^2)/sqrt3
=(1+3)/sqrt3
=4/sqrt3
Comment: You have it right.
Cheers,
Stan H.
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