SOLUTION: 4y + square root 3 x = 8 3y + 4x = -6 Is there a solution - how do I graph this system? Please help. Thanks

Algebra ->  Square-cubic-other-roots -> SOLUTION: 4y + square root 3 x = 8 3y + 4x = -6 Is there a solution - how do I graph this system? Please help. Thanks      Log On


   

Question 58708: 4y + square root 3 x = 8
3y + 4x = -6
Is there a solution - how do I graph this system? Please help.
Thanks
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1st: 4y + square root 3 x = 8
2nd: 3y + 4x = -6
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Multiply 1st by 3 and 2nd by 4 to get:
3rd: 12y+3sqrt3 x = 24
4th: 12y+16x = -24
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Subtract 4th from 3rd to get:
5th: (3sqrt3 -16)x=48
x=48/(3sqrt3 - 16)
x=-4.44286...
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Substitute in 2nd to solve for y, as follows:
3y +4(-4.442861643)=-6
3y - 17.7714467...=-6
3y=11.77144657...
y=3.923815524...
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These value check in 3rd
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You should be able to graph the original equations as:
y=(1/4)(8-(sqrt3)x)
y=(1/3)(-6-4x)

Cheers,
Stan H.