SOLUTION: I need to complete the square and find the two "x" answers. 2x^2-26=0 I know to add 139 to each side but dont know where to go from there!

Algebra ->  Square-cubic-other-roots -> SOLUTION: I need to complete the square and find the two "x" answers. 2x^2-26=0 I know to add 139 to each side but dont know where to go from there!       Log On


   



Question 553511: I need to complete the square and find the two "x" answers.
2x^2-26=0
I know to add 139 to each side but dont know where to go from there!

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Did you mean x^2 -26x = 0???

If so, there are TWO steps: Take HALF of the x coefficient, and SQUARE! Half of 26 is 13, and 13 squared is 169. (If this is NOT what you meant, send me an Email, and let me know what you really did mean.)
x^2 - 26x = 0

Half of 26 is 13, and 13 squared is 169, so you add 169 to each side of the equation.

x^2 - 26x + 169 = 0 + 169
(x-13)^2 = 169

Take the square root of each side:
x-13+=+0%2B-sqrt%28169%29
x-13+=+0%2B-13
x+=+13+%2B-13
x=13%2B13 or x=13-13
x=26 or x=0

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Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus