SOLUTION: Please help w/ the following: Solve(3x+3)^2=16 Thank you.

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Question 55250: Please help w/ the following:
Solve(3x+3)^2=16
Thank you.
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
Solve %283x%2B3%29%5E2=16
Use the square root property:
For any real number c, if x%5E2=c, then x=sqrt%28c%29 or x=-sqrt%28c%29.
%283x%2B3%29%5E2=16
sqrt%28%283x%2B3%29%5E2%29=%2B-sqrt%2816%29
3x%2B3=4 or 3x%2B3=-4
3x%2B3-3=4-3 or 3x%2B3-3=-4-3
3x=1 or 3x=-7
3x%2F3=1%2F3 or 3x%2F3=-7%2F3
highlight%28x=1%2F3%29 or highlight%28x=-7%2F3%29
:
Check:
if x=1/3
%283%281%2F3%29%2B3%29%5E2=16
%281%2B3%29%5E2=16
4%5E2=16
16=16 x=1/3 checks out.
if x=-7/3
%283%28-7%2F3%29%2B3%29%5E2=16
%28-7%2B3%29%5E2=16
%28-4%29%5E2=16
16=16 x=-7/3 also check out, so we're right!!!
Happy Calculating!!!