SOLUTION: Find the perimeter where width = (sqrt)27 feet length = 4(sqrt)12 feet The perimeter is ___________ __>

Algebra ->  Square-cubic-other-roots -> SOLUTION: Find the perimeter where width = (sqrt)27 feet length = 4(sqrt)12 feet The perimeter is ___________ __>      Log On


   

Question 493663: Find the perimeter where width = (sqrt)27 feet
length = 4(sqrt)12 feet
The perimeter is ______________>
Answer by MRperkins(300) About Me  (Show Source):
You can put this solution on YOUR website!
assuming this is a rectangle, then P=2W+2L
sqrt%2827%29=3sqrt%283%29
and 4sqrt%2812%29=4%2A2sqrt%283%29=8sqrt%283%29
so
P=2%2A3sqrt%283%29%2B2%2A8sqrt%283%29
=
P=6sqrt%283%29%2B16sqrt%283%29
=
P=22sqrt%283%29