SOLUTION: How do you find the inverse of f(x)= 1/(x^2) or f(x)=1/(x^3)? I don't really have a problem with finding inverses but I can't figure out these two. I usually switch x and y, so ca

Algebra ->  Square-cubic-other-roots -> SOLUTION: How do you find the inverse of f(x)= 1/(x^2) or f(x)=1/(x^3)? I don't really have a problem with finding inverses but I can't figure out these two. I usually switch x and y, so ca      Log On


   



Question 483944: How do you find the inverse of f(x)= 1/(x^2) or f(x)=1/(x^3)?
I don't really have a problem with finding inverses but I can't figure out these two. I usually switch x and y, so can anyone explain it to me in that manner? A detailed answer is really what I need. Thank you, in advance!

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
How do you find the inverse of f(x)= 1/(x^2) or f(x)=1/(x^3)?
:
y = 1%2Fx%5E2%29
swap x and y and then find y
x = 1%2Fy%5E2%29
multiply both sides by y^2
xy^2 = 1
divide both sides by x
y^2 = 1%2Fx
Find the square root of both sides
y = sqrt%281%2Fx%29
:
f(x) = 1/(x^3) is the same except its the cube root of 1/x