SOLUTION: Given g(x)= square root of 2x+2, find four points on the graph of the function.

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Question 469109: Given g(x)= square root of 2x+2, find four points on the graph of the function.
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
g%28x%29=+sqrt%282x%2B2%29
If x=-1 then g%28-1%29=+sqrt%282%2A%28-1%29%2B2%29=sqrt%280%29=0, point (-1,0)
If x=1 then g%281%29=+sqrt%282%2A1%2B2%29=sqrt%284%29=2, point (1,2)
If x=3.5 then g%283.5%29=+sqrt%282%2A3.5%2B2%29=sqrt%289%29=3, point (3.5,3)
If x=7 then g%287%29=+sqrt%282%2A7%2B2%29=sqrt%2816%29=4, point (7,4)
Answer: (-1,0), (1,2), (3.5,3), (7,4)