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Hi,
If I am understanding Your question properly:
|squaring both sides of the Eq
7x + 36 = (x+4)^2
7x + 36 = x^2 + 8x + 16
x^2 + x - 20 = 0
(x+5)(x-4)=0 Note:SUM of the inner product(5x) and the outer product(-4x) = x
(x+5)=0 x = -5 |Extraneous solution sqrt(1) ≠ -1
(x-4)=0 x = 4