SOLUTION: Set up an equation and solve the problem:
The sum of the ares of two squares is 4,477 square inches. Each side of the larger square is 6 times the length of a side of the smalle
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-> SOLUTION: Set up an equation and solve the problem:
The sum of the ares of two squares is 4,477 square inches. Each side of the larger square is 6 times the length of a side of the smalle
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Question 378931: Set up an equation and solve the problem:
The sum of the ares of two squares is 4,477 square inches. Each side of the larger square is 6 times the length of a side of the smaller square. Find the length of a side of the smaller square.
Thanks in advance! Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The sum of the areas of two squares is 4,477 square inches.
Each side of the larger square is 6 times the length of a side of the smaller square.
Find the length of a side of the smaller square.
:
Let x = side of the small square
then
6x = side of the large square
:
Large sq area + small sq area = 4477
(6x)^2 + x^2 = 4477
36x^2 + x^2 = 4477
37x^2 = 4477
Divide both sides by 37, results
x^2 = 121
x =
x = 11 inches is the side of the smaller square
:
:
Check solution by finding the total area
66^2 + 11^2 =
4356 + 121 = 4477, confirms our answer
