SOLUTION: solve using the quadratic formula 2x^2+3x+4=0

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Question 371393: solve using the quadratic formula
2x^2+3x+4=0
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
2x%5E2%2B3x%2B4=0

Compare to

ax%5E2%2Bbx%2Bc=0

a=2, b=3,  c=4

Sustitute those values in

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

x+=+%28-%283%29+%2B-+sqrt%28+%283%29%5E2-4%2A%282%29%2A%284%29+%29%29%2F%282%2A%282%29%29+

x+=+%28-3+%2B-+sqrt%289-32+%29%29%2F4+

x+=+%28-3+%2B-+sqrt%28-23%29%29%2F4+

x+=+%28-3+%2B-+i%2Asqrt%2823%29%29%2F4+

Write as separate fractions:

x+=+-3%2F4+%2B-+expr%28sqrt%2823%29%2F4%29i+

Edwin