SOLUTION: Solve for equation: square root 2X-1 minus square root X-5 = 3 not sure, will that be 2X times X and 2X times 5 - 1 times X and 1-5 under square root?

Algebra ->  Square-cubic-other-roots -> SOLUTION: Solve for equation: square root 2X-1 minus square root X-5 = 3 not sure, will that be 2X times X and 2X times 5 - 1 times X and 1-5 under square root?      Log On


   

Question 342200: Solve for equation: square root 2X-1 minus square root X-5 = 3
not sure, will that be 2X times X and 2X times 5 - 1 times X and 1-5 under square root?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%282x-1%29-sqrt%28x-5%29+=+3
sqrt%282x-1%29=sqrt%28x-5%29+%2B+3
Square both sides,
2x-1=%28x-5%29%2B6sqrt%28x-5%29%2B9
2x-1=%28x%2B4%29%2B6sqrt%28x-5%29
x-5=6sqrt%28x-5%29
Use a substitution, let u=x-5
u=6sqrt%28u%29
Square both sides,
u%5E2=36u
u%5E2-36u=0
u%28u-36%29=0
Two solutions:
u=0
x-5=0
highlight%28x=5%29
.
.
.
u-36=0
u=36
x-5=36
highlight%28x=41%29