SOLUTION: (1) sqrt of 7 divided by the sqrt of 18 (2) sqrt of 27 divided by sqrt of 16 (3) 6 divided by 3-sqrt of 18 Could someone walk me through the steps for these problem

Algebra ->  Square-cubic-other-roots -> SOLUTION: (1) sqrt of 7 divided by the sqrt of 18 (2) sqrt of 27 divided by sqrt of 16 (3) 6 divided by 3-sqrt of 18 Could someone walk me through the steps for these problem       Log On


   



Question 339095: (1) sqrt of 7 divided by the sqrt of 18
(2) sqrt of 27 divided by sqrt of 16
(3) 6 divided by 3-sqrt of 18

Could someone walk me through the steps for these problem because I totally have no clue how to solve these? Thank you.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
(1) sqrt of 7 divided by the sqrt of 18
= sqrt%287%2F18%29
= sqrt%2814%2F36%29
= sqrt%2814%29%2F6
--------------------
(2) sqrt of 27 divided by sqrt of 16
Hint: 27 = 3*9 and 16 = 4*4
---------------
(3) 6 divided by 3-sqrt of 18
6%2F%283-sqrt%2818%29%29
Multiply NUM and DEN by the conjugate of the DEN
= 6%283%2Bsqrt%2818%29%29%2F%28%283%2Bsqrt%2818%29%29%2A%283-sqrt%2818%29%29%29
= %2818+%2B+6sqrt%2818%29%29%2F%289+-+18%29
= %2818+%2B+18sqrt%282%29%29%2F%28-9%29
= -2+-+2sqrt%282%29