SOLUTION: solve by taking square roots:
6(x+3)^2=24 Simple:
obtain square roots of both sides: sqr(6)(x+3)=2sqr(6)
factor out sqr(6): (x+3)=2
subtract 3 from both side
Algebra ->
Square-cubic-other-roots
-> SOLUTION: solve by taking square roots:
6(x+3)^2=24 Simple:
obtain square roots of both sides: sqr(6)(x+3)=2sqr(6)
factor out sqr(6): (x+3)=2
subtract 3 from both side
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Question 329285: solve by taking square roots:
6(x+3)^2=24 Simple:
obtain square roots of both sides: sqr(6)(x+3)=2sqr(6)
factor out sqr(6): (x+3)=2
subtract 3 from both sides you get: x= -1 Answer by coyparra@yahoo.com(2) (Show Source):
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