SOLUTION: Simplest radical form: {{{sqrt(24a^6b^17c^5)}}}

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Question 324113: Simplest radical form:
sqrt%2824a%5E6b%5E17c%5E5%29

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!


sqrt%2824a%5E6b%5E17c%5E5%29
24 contains the perfect square 4 as a factor, so write 24 as 4*6
Any even power of a letter is a perfect square, so
1. since a%5E6 is an even power of a letter, we leave it as it is right now.
2. since b%5E17 is an odd power of a letter, we write it as the largest even
power times the letter to the first power, so write it as b%5E16b%5E1
or just b%5E16%2Ab
3. since c%5E5 is an odd power of a letter, we write it as the largest even
power times the letter to the first power, so write it as c%5E4b%5E1, or just c%5E4%2Ac
So
sqrt%2824a%5E6b%5E17c%5E5%29
becomes
sqrt%284%2A6%2Aa%5E6%2Ab%5E16%2Ab%2Ac%5E4%2Ac%29
or making it colorful:

The ones I have colored red come out out of the radical
and the ones I have colored green stay underneath.
When we take the square root of the 4 we write 2 in front
of the radical. When we take the square root of the
even power of a letter out front we must divide the even
exponent by 2:

or just
2a%5E3b%5E8c%5E2sqrt%286bc%29
Edwin