SOLUTION: -d = 3 sqrt () d-2 a) {3} b) {6} c) {3,6} d) none

Algebra ->  Square-cubic-other-roots -> SOLUTION: -d = 3 sqrt () d-2 a) {3} b) {6} c) {3,6} d) none      Log On


   

Question 313915: -d = 3 sqrt () d-2
a) {3}
b) {6}
c) {3,6}
d) none
Found 2 solutions by rapaljer, solver91311:
Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Without even working this out, I would say there is NO SOLUTION.

Given that your problem was -d+=+3%2Asqrt%28d-2%29,
if d is a positive number, then you have a negative number equal to a square root, which is no real solution.

If d is a negative number, then you end up with a negative inside the square root, which is NO REAL SOLUTION.

If d=0, that doesn't work either.

No solution!!

Dr. Robert J. Rapalje, Retired

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


By definition, . Also, . Therefore the product of and must be a positive number or zero. But both possibilities given for , and indeed both of the calculated possibilities for if you solve the equation (same thing), are positive numbers. That means that is a negative number. A negative number cannot be equal to a positive number, therefore, no solution.

And why don't you pay attention? Last time I answered one of your questions I told you that it is easier for us to read your problems if you put the radicand INSIDE the parentheses after sqrt, thus:

-d = 3 sqrt (d - 2)

John