SOLUTION: Please help me solve this problem: {{{ 4= sqrt (x-3^2) }}}

Algebra ->  Square-cubic-other-roots -> SOLUTION: Please help me solve this problem: {{{ 4= sqrt (x-3^2) }}}      Log On


   



Question 311403: Please help me solve this problem: ++4=+sqrt+%28x-3%5E2%29++
Found 2 solutions by Miceandwine, solver91311:
Answer by Miceandwine(15) About Me  (Show Source):
You can put this solution on YOUR website!
++4=+sqrt+%28x-3%5E2%29++
First, I would recommend squaring both sides.
4^2=x-3^2
Then, I would solve the square roots.
16=x-9
Then, add 9 to both sides
9+16=x-9+9
Finally,
x=25
I hope I helped!

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Square both sides.

Add 9 to both sides.

That will solve exactly what you have written.

But if you really meant:



Then

Square both sides.

Take the square root of both sides, remembering to consider both the positive and negative roots.

Solve the two resulting equations by adding 3 to both sides of each equation.

John