SOLUTION: How do I solve this equation and check for extraneous solutions? 3 sqrt w + 1 = 6

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Question 309501: How do I solve this equation and check for extraneous solutions?
3 sqrt w + 1 = 6
Found 2 solutions by unlockmath, stanbon:
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
Let's first divide by 3 to get:
sqrt w + 1 = 2 square this equation to get:
w + 1 = 4 Subtract 1 from both sides to get:
w=3
Make sense?
RJ
www.math-unlock.om

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do I solve this equation and check for extraneous solutions?
3 sqrt(w + 1) = 6
----
sqrt(w+1) = 2
w+1 = 4
w = 3
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Checking:
3*sqrt(4) = 6
3*2 = 6
-----
Solution: w = 3
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Cheers,
Stan H.