SOLUTION: Here's the problem: Simplify by taking the roots of the numerator and denominator. Assume that all expressions under radicals represent positive numbers. {{{ cube root ((27x^5)/(y^

Algebra ->  Square-cubic-other-roots -> SOLUTION: Here's the problem: Simplify by taking the roots of the numerator and denominator. Assume that all expressions under radicals represent positive numbers. {{{ cube root ((27x^5)/(y^      Log On


   

Question 306119: Here's the problem: Simplify by taking the roots of the numerator and denominator. Assume that all expressions under radicals represent positive numbers. +cube+root+%28%2827x%5E5%29%2F%28y%5E3%29%29+

The answer I have is (3 cube root of (x^5))/y)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
3sqrt%28%2827x%5E5%29%2F%28y%5E3%29%29+
Factor to reveal the perfect cubes
3sqrt%28%2827%2Ax%5E3%2Ax%5E2%29%2F%28y%5E3%29%29+
extract those cubes and you have
%28%283x%29%2Fy%29%2A3sqrt%28%28x%5E2%29%29+