SOLUTION: The formula for the period of a pendulum is t=2[pi]sqrt(L/G) where t is the period in seconds, L is its length in feet, and G is t he acceleration of gravity. On earth, gravity is
Algebra ->
Square-cubic-other-roots
-> SOLUTION: The formula for the period of a pendulum is t=2[pi]sqrt(L/G) where t is the period in seconds, L is its length in feet, and G is t he acceleration of gravity. On earth, gravity is
Log On
Question 297610: The formula for the period of a pendulum is t=2[pi]sqrt(L/G) where t is the period in seconds, L is its length in feet, and G is t he acceleration of gravity. On earth, gravity is 32 ft / sec^2. The formula when used on Earth becomes t=2[pi]sqrt(L/32).
Find the period of a pendulum whose length is 8 feet. Answer by nyc_function(2741) (Show Source):
You can put this solution on YOUR website!
Let t = period in seconds.
Let L = length in feet.
Let pi = 3.14
Just plug and chug.
We are looking for t (in seconds).
Here is the set up:
t = 2(3.14)*sqrt{8/32}
We now use a calculator.
t = 6.28(0.5)
t = 3.14 seconds.
