SOLUTION: my question say's that the square root of 12 minus the square root of 3 equals k multiplied by the square root of three and wants me to find what k would equal. can you explain how

Algebra ->  Square-cubic-other-roots -> SOLUTION: my question say's that the square root of 12 minus the square root of 3 equals k multiplied by the square root of three and wants me to find what k would equal. can you explain how      Log On


   

Question 292730: my question say's that the square root of 12 minus the square root of 3 equals k multiplied by the square root of three and wants me to find what k would equal. can you explain how to find k
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%2812%29-sqrt%283%29=k%2Asqrt%283%29 Start with the given equation.


sqrt%284%2A3%29-sqrt%283%29=k%2Asqrt%283%29 Factor 12 into 4*3. Note: 4 is a perfect square.


sqrt%284%29%2Asqrt%283%29-sqrt%283%29=k%2Asqrt%283%29 Break up the first root.


2%2Asqrt%283%29-sqrt%283%29=k%2Asqrt%283%29 Take the square root of 4 to get 2.


%282-1%29%2Asqrt%283%29=k%2Asqrt%283%29 Factor out the GCF sqrt%283%29


1%2Asqrt%283%29=k%2Asqrt%283%29 Combine like terms.


1=k Divide both sides by sqrt%283%29 to isolate 'k'.


So we can see that the solution is k=1 which essentially means that sqrt%2812%29-sqrt%283%29=1%2Asqrt%283%29 or more simply sqrt%2812%29-sqrt%283%29=sqrt%283%29