SOLUTION: root of -8 / x, the problem has a little 3 in front of the root sign. I need to rationalize the denominator.

First we can always take a negative out of a radical if the

index of the radical is odd. The index is 3 (That's the 

little 3 in front of the root sign) and therefore odd. So

let's take the negative sign outside:







So we need to get an exponent of 3 in the denominator.  There is

an  there, but we need there to be an  there, so

we multiply top and bottom by 











Now we use the principle "The cube root of a quotient equals

the quotient of cube roots".



  



The denominator is now the cube root of a cube, so

that takes away the radical and the exponent, and just

leaves x in the bottom.







Only one thing left to do, and that is to take the 

cube root of 8 which is 2, and put 2 on the outside

of the cube root: