SOLUTION: April, Mae, June and Julie were born in consecutive years, in that order, with April being the oldest. All they will tell you is that the sum of the squares of their ages is 534.
Algebra ->
Square-cubic-other-roots
-> SOLUTION: April, Mae, June and Julie were born in consecutive years, in that order, with April being the oldest. All they will tell you is that the sum of the squares of their ages is 534.
Log On
Question 265728: April, Mae, June and Julie were born in consecutive years, in that order, with April being the oldest. All they will tell you is that the sum of the squares of their ages is 534. How old are they? Answer by solver91311(24713) (Show Source):
Let represent April's age. Then is Mae, is June, and is Julie.
The sum of the squares of their ages:
Giving you an easily factorable quadratic. Discard the negative root because ages of people are positive numbers. The positive root is April's age and you just count down for the other three.
