SOLUTION: How do I solve this by using the square root property? x^2=180

Algebra ->  Square-cubic-other-roots -> SOLUTION: How do I solve this by using the square root property? x^2=180      Log On


   



Question 242158: How do I solve this by using the square root property?
x^2=180

Found 3 solutions by College Student, rapaljer, dpaulin:
Answer by College Student(505) About Me  (Show Source):
You can put this solution on YOUR website!
In order to determine the value of x, we need to take the square root of both sides of the equation. In this case, we will not get a nice integer, instead we will get a decimal result. But that's ok... it doesn't mean that is wrong, it is just uncommon. Most problems are setup in such a way to yield whole numbers (integers).
.
Problem:
x%5E2=180
sqrt%28x%5E2%29=sqrt%28180%29
Note: when we take the square root of a squared exponent, they cancel each other out. So, we are left with:
x=sqrt%28180%29
Now, you may leave it like this sqrt%28180%29 or calculate the decimal equivalent using your calculator. Which would be: x=13.42 <-- result has been rounded.

Answer by rapaljer(4671) About Me  (Show Source):
You can put this solution on YOUR website!
Take the square root of each side of the equation, giving you

x%5E2=180
x=0%2B-sqrt%28180%29

NOTE: You really don't need the 0 in front of the +/-, but the algebra.com notation requires that I put it there!

x=0%2B-sqrt%2836%29%2Asqrt%285%29
x=6sqrt%285%29 or x=-6sqrt%285%29

Dr. Robert J. Rapalje, Retired
Seminole State College of Florida

Answer by dpaulin(12) About Me  (Show Source):
You can put this solution on YOUR website!
square root both sides of the equation
x%5E2=180
sqrt%28x%5E2%29=sqrt%28180%29
x=6sqrt%285%29