SOLUTION: 3 over 7 minus the square root of 2 Okay so I multiplyed by the opposite, which would be 7 plus square root of 2 on both the deonominator and top. I got 21 + 3 to the radical of

Algebra ->  Square-cubic-other-roots -> SOLUTION: 3 over 7 minus the square root of 2 Okay so I multiplyed by the opposite, which would be 7 plus square root of 2 on both the deonominator and top. I got 21 + 3 to the radical of       Log On


   

Question 235092: 3 over 7 minus the square root of 2
Okay so I multiplyed by the opposite, which would be 7 plus square root of 2 on both the deonominator and top.
I got 21 + 3 to the radical of 2 over 47
Did I do this right or am I totally wrong?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
3 / (7-sqrt(2))

To remove the square root from the denominator, multiply numerator and denominator by (7+sqrt(2)

you get:

3 * (7+sqrt(2)) / 49 - 2 which equals:

21 + 3*sqrt(2) / 47

If "21 + 3 to the radical of 2 over 47" is the same as "21 + 3*sqrt(2)" then you got it right.

sqrt(2) looks like sqrt%282%29 after going through the algebra.com formula generator.

It's not 3 to the radical of 2.

It would be 3 times the radical of 2.

I would say it as 3 times the square root of 2.

The answer would look like %2821+%2B+3%2Asqrt%282%29%29%2F47