SOLUTION: please help me solve simplify: {{{sqrt (40x^2) * sqrt (10x) }}}

Algebra ->  Square-cubic-other-roots -> SOLUTION: please help me solve simplify: {{{sqrt (40x^2) * sqrt (10x) }}}      Log On


   



Question 223169: please help me solve simplify: sqrt+%2840x%5E2%29+%2A+sqrt+%2810x%29+
Found 2 solutions by jim_thompson5910, Edwin McCravy:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt%2840x%5E2%29%2Asqrt%2810x%29 Start with the given expression.


sqrt%28%2840x%5E2%29%2810x%29%29+ Combine the roots.


sqrt%28400x%5E3%29 Multiply


sqrt%28400%29%2Asqrt%28x%5E3%29 Break up the root.


sqrt%28400%29%2Asqrt%28x%5E2%2Ax%29 Factor


sqrt%28400%29%2Asqrt%28x%5E2%29%2Asqrt%28x%29 Break up the root again.


20%2Asqrt%28x%5E2%29%2Asqrt%28x%29 Take the square root of 400 to get 20.


20%2Ax%2Asqrt%28x%29 Take the square root of x%5E2 to get 'x'.


So sqrt%2840x%5E2%29%2Asqrt%2810x%29=20x%2Asqrt%28x%29 where x%3E=0

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
sqrt+%2840x%5E2%29+%2A+sqrt+%2810x%29+

First take the square root of x%5E2 
in the first factor, which gives x in front
of the first radical 

x%2Asqrt+%2840%29+%2A+sqrt+%2810x%29+

Multiply under the radicals and form just one
radical:

x%2Asqrt+%28400x%29+

Now take the square root of the 400 which
gives 20 in front of the radical.

20x%2Asqrt%28x%29+

Edwin