SOLUTION: I have to find the derivative of the equation y= the square root of x plus the cube root of x and the who equation is then squared. to help the equation would look like the y=(x ^1
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-> SOLUTION: I have to find the derivative of the equation y= the square root of x plus the cube root of x and the who equation is then squared. to help the equation would look like the y=(x ^1
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Question 213689: I have to find the derivative of the equation y= the square root of x plus the cube root of x and the who equation is then squared. to help the equation would look like the y=(x ^1/2 + x^2/3)^2 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Use the chain rule to find the derivative.
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y=(x ^1/2 + x^2/3)^2
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y' = [2(x^(1/2)+x^(2/3)] * [(1/2)x^(-1/2) + (2/3)x^(-1/3)]
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Cheers,
Stan H.
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