SOLUTION: What are the roots of 3x^3-48x=0? 0,-4, and 4 Please correct me if I am wrong.

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Question 194312This question is from textbook saxon algebra 2
: What are the roots of 3x^3-48x=0?
0,-4, and 4
Please correct me if I am wrong. This question is from textbook saxon algebra 2

Found 2 solutions by Earlsdon, checkley77:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You are correct!
3x%5E3-48x+=+0 Factor out 3x.
3x%28x%5E2-16%29+=+0 Apply the zero product rule:
3x+=+0 or x%5E2-16+=+0
3x+=+0 so highlight%28x+=+0%29 and...
x%5E2+=+16 so highlight%28x+=+4%29 or highlight%28x+=+-4%29

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
3x^3-48x=0
3x(x^2-16)=0
3x=0
x=0/3
x=0 ans.
x^2-16=0
x^2=16
x=sqrt16
x=+/-4 ans.