SOLUTION: Can you please help me solve this problem? [(the square root of 2)+(3)]times[(the square root of 3)-(4)]

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Question 190604: Can you please help me solve this problem? [(the square root of 2)+(3)]times[(the square root of 3)-(4)]
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%28sqrt%282%29%2B3%29%28sqrt%283%29-4%29 Start with the given expression.


Now let's FOIL the expression.


Remember, when you FOIL an expression, you follow this procedure:


%28highlight%28sqrt%282%29%29%2B3%29%28highlight%28sqrt%283%29%29-4%29 Multiply the First terms:%28sqrt%282%29%29%2A%28sqrt%283%29%29=sqrt%286%29.


%28highlight%28sqrt%282%29%29%2B3%29%28sqrt%283%29%2Bhighlight%28-4%29%29 Multiply the Outer terms:%28sqrt%282%29%29%2A%28-4%29=-4%2Asqrt%282%29.


%28sqrt%282%29%2Bhighlight%283%29%29%28highlight%28sqrt%283%29%29-4%29 Multiply the Inner terms:%283%29%2A%28sqrt%283%29%29=3%2Asqrt%283%29.


%28sqrt%282%29%2Bhighlight%283%29%29%28sqrt%283%29%2Bhighlight%28-4%29%29 Multiply the Last terms:%283%29%2A%28-4%29=-12.


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So we have the terms: sqrt%286%29, -4%2Asqrt%282%29, 3%2Asqrt%283%29, -12


sqrt%286%29-4%2Asqrt%282%29%2B3%2Asqrt%283%29-12 Now add every term listed above to make a single expression.


So %28sqrt%282%29%2B3%29%28sqrt%283%29-4%29 FOILs to sqrt%286%29-4%2Asqrt%282%29%2B3%2Asqrt%283%29-12.


In other words, %28sqrt%282%29%2B3%29%28sqrt%283%29-4%29=sqrt%286%29-4%2Asqrt%282%29%2B3%2Asqrt%283%29-12.