SOLUTION: Solve each equation by factoring or taking square roots. 1.) x^2 - 7x = 0 2.) x^2 + 2x - 8 = 0 3.) (x+3)^2 = 9 4.) 2x^2 - 6x - 8 = 0

Algebra ->  Square-cubic-other-roots -> SOLUTION: Solve each equation by factoring or taking square roots. 1.) x^2 - 7x = 0 2.) x^2 + 2x - 8 = 0 3.) (x+3)^2 = 9 4.) 2x^2 - 6x - 8 = 0      Log On


   

Question 175624: Solve each equation by factoring or taking square roots.
1.) x^2 - 7x = 0
2.) x^2 + 2x - 8 = 0
3.) (x+3)^2 = 9
4.) 2x^2 - 6x - 8 = 0
Found 2 solutions by EMStelley, stanbon:
Answer by EMStelley(208) About Me  (Show Source):
You can put this solution on YOUR website!
I will do the first one for you, and you can try the rest (should not ask more than one question per post).
x%5E2-7x+=+x%28x-7%29=0
So
x=0+and+x-7=0
Thus x=0 and x=7

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve each equation by factoring or taking square roots.
1.) x^2 - 7x = 0
x(x-7)=0
Since the product is zero, one of the factors must be zero.
x = 0 or x-7 = 0
x = 0 or x = 7
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2.) x^2 + 2x - 8 = 0
(x+4)(x-2) = 0
x = -4 or x = 2
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3.) (x+3)^2 = 9
x+3 = 3 or x+3=-3
x = 0 or x= -6
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4.) 2x^2 - 6x - 8 = 0
2(x^2 - 3x -4 = 0
2(x-4)(x+1) = 0
x = 4 or x = -1
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Cheers,
Stan H.