SOLUTION: I have a problem on a homework sheet that looks like this: I am not sure where to even start. I would think that since both the numerator and denominator are both the 4th root I co

Algebra ->  Square-cubic-other-roots -> SOLUTION: I have a problem on a homework sheet that looks like this: I am not sure where to even start. I would think that since both the numerator and denominator are both the 4th root I co      Log On


   



Question 168716: I have a problem on a homework sheet that looks like this: I am not sure where to even start. I would think that since both the numerator and denominator are both the 4th root I could just multiply everything under the radical. Could you please help.
Thank you :)
Simplify:
4√a^6b^13/4√a^2b

Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
4√a^6b^13/4√a^2b
= 4th root of[(a^6b^13/a^2b]
= 4 th root of [a^4b^12]
= ab^3
============
Cheers,
Stan H.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify:
4√a^6b^13/4√a^2b
------------------
It's not completely clear what the expression is.
If it's:
%28%28a%5E6b%5E13%29%5E%281%2F4%29%29%2F%28%28a%5E2b%29%5E%281%2F4%29%29
=%28%28a%5E6b%5E13%29%2F%28a%5E2b%29%29%5E%281%2F4%29
=%28a%5E4b%5E12%29%5E%281%2F4%29
=ab%5E3