SOLUTION: sqrt of x-6 - sqrt of x-6 = 2
I got this:
sqrt of -x+6 - sqrt x-6 = 2
sqrt of -x+6 - sqrt -x+6 = 2
answer of 0=2, so the final answer is 0.
I am supposed to check for ex
Algebra ->
Square-cubic-other-roots
-> SOLUTION: sqrt of x-6 - sqrt of x-6 = 2
I got this:
sqrt of -x+6 - sqrt x-6 = 2
sqrt of -x+6 - sqrt -x+6 = 2
answer of 0=2, so the final answer is 0.
I am supposed to check for ex
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Question 147207: sqrt of x-6 - sqrt of x-6 = 2
I got this:
sqrt of -x+6 - sqrt x-6 = 2
sqrt of -x+6 - sqrt -x+6 = 2
answer of 0=2, so the final answer is 0.
I am supposed to check for extraneous answers also. Are my calculations correct? How do I figure for extraneous answers?
Thank you for your help. Answer by jim_thompson5910(35256) (Show Source):
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