SOLUTION: 2x^2-4x+16=0
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Question 131655
:
2x^2-4x+16=0
Answer by
stanbon(75887)
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2x^2-4x+16=0
x^2-2x+8 = 0
(x-4)(x+2)=0
x = 4 or x=-2
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Cheers,
Stan H.