SOLUTION: +square root of 49a^4b^8c^12=?

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Question 124218: +square root of 49a^4b^8c^12=?
Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
You are asked to find the square root of:
.
49a%5E4b%5E8c%5E12
.
Split this into the product of individual terms as follows:
.
%2849%29%2A%28a%5E4%29%2A%28b%5E8%29%2A%28c%5E12%29
.
Now take the square root of the terms in each set of parentheses. For the 49, the square
root is 7. In the remaining terms the square root of each is found by dividing the exponent
by 2.
.
So
sqrt%28a%5E4%29+=+a%5E2
.
sqrt%28b%5E8%29+=+b%5E4
.
and sqrt%28c%5E12%29+=+c%5E6
.
The final answer is just the product of all the individual square roots. Therefore, it is:
.
7%2Aa%5E2%2Ab%5E4%2Ac%5E6
.
Hope this helps you to understand how the problem can be done.
.