SOLUTION: Please help solve for the following equation:
A) If y= sqrt x+2, fill in for x=0,1,2,3,4. Round to the nearest three decimal places where necessary.
Please show work
B)
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-> SOLUTION: Please help solve for the following equation:
A) If y= sqrt x+2, fill in for x=0,1,2,3,4. Round to the nearest three decimal places where necessary.
Please show work
B)
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A) If y= sqrt x+2, fill in for x=0,1,2,3,4. Round to the nearest three decimal places where necessary.
Please show work
B) Explain why no negative values are chosen as values to substitute in for x
Thank you in advance This question is from textbook blitzer college algebra
You can put this solution on YOUR website! A. for x=0
y=sqrt x+2
= sqrt 0+2
= sqrt 2
=1.414 approx
for x = 1
y = sqrt x+2
= sqrt 1+2
=sqrt 3
= 1.732 approx
for x=2
y=sqrt x+2
= sqrt 2+2
=sqrt 4
=2
for x=3
y=sqrt x+2
=sqrt3+2
=sqrt 5
= 2.23 approx
for x=4
y=sqrt x+2
=sqrt 4+2
=sqrt 6
= 2.449 approx
B. Negative 1 and negative two can be values for x
for x= -1
y=sqrt x+2
=sqrt -1+2
=sqrt 1
=1
also x=-2
y=sqrt -2+2
=sqrt 0
=0
Values lower than -2 cannot be used because the radicand becomes negative, and will yield to imaginary number.
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