SOLUTION: Solve the equation. 2y^2-3y-6=0

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Question 122491: Solve the equation. 2y^2-3y-6=0
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
2y%5E2-3y-6=0
y+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ Use the quadratic equation.
y+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%2A2%2A%28-6%29+%29%29%2F%282%2A2%29+
y+=+%283+%2B-+sqrt%28+9%2B48+%29%29%2F%284%29+
y+=+%283+%2B-+sqrt%28+57+%29%29%2F%284%29+ Two real solutions.
Exactly the roots are,
y%5B1%5D+=+%283+%2B+sqrt%28+57+%29%29%2F%284%29+
y%5B2%5D+=+%283+-+sqrt%28+57+%29%29%2F%284%29+
or approximately,
y%5B1%5D+=+2.637
y%5B2%5D+=+-1.137
+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+2x%5E2-3x-6%29+