SOLUTION: Why does √xy = √x√y?

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Question 1208358: Why does √xy = √x√y?



Answer by mccravyedwin(408) About Me  (Show Source):
You can put this solution on YOUR website!
To prove sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29

Let x and y be non-negative real numbers. 

lemma: square roots of non-negative real numbers are unique.

Proof:
For contradiction, suppose for positive real number " a ", p and q 
are two different non-negative square roots of " a ".  Then,

p%5E2=q%5E2=a => p%5E2-q%5E2=0 => %28p-q%29%28p%2Bq%29=0 
since p%2Bq%3E=0, p-q=0, so p=q.  So we have reached a contradiction 
namely, that p and q are NOT different.

We show that the squares of sqrt%28x%2Ay%29 and sqrt%28x%29%2Asqrt%28y%29 are equal.

%28sqrt%28x%2Ay%29%29%5E2%22%22=%22%22x%2Ay

%28sqrt%28x%29%2Asqrt%28y%29%29%5E2%22%22=%22%22%28sqrt%28x%29%2Asqrt%28y%29%29%28sqrt%28x%29%2Asqrt%28y%29%29%22%22=%22%22sqrt%28x%29%2Asqrt%28x%29%2Asqrt%28y%29%2Asqrt%28y%29%22%22=%22%22%28sqrt%28x%29%29%5E2%28sqrt%28y%29%29%5E2%22%22=%22%22x%2Ay

Therefore %28sqrt%28x%2Ay%29%29%5E2=%28sqrt%28x%29%2Asqrt%28y%29%29%5E2

and by the lemma, sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29

PROVED.

Edwin